Paasa Ke Prashn पासा के प्रश्न

Sol : Option C
From figures (ii) and (iii), we can conclude that the numbers 2, 4, 3, and 6 appear adjacent to the letter 5. Therefore, the number 1 appears opposite to 5. In other words, 5 appears opposite to 1.

Sol : Option B
From figures (i) and (ii), we can conclude that the alphabets C, D, A and E lie adjacent to the alphabet F. So, the alphabet B lies opposite F and conversely F lies opposite B.

Sol : Option D
From figures (i), (ii) and (iv), we can conclude that F, D, C and A lie adjacent to B. Hence, E must lie opposite to B.

Sol : Option C
The pattern on the fig. (X) and the fact that the faces are rectangular and fig.(2) is eliminated as dot on the upper face is on left side instead of right.
Fig. (3) and fig.(4) also get eliminated as the smaller rectangular faces should be blank instead of having a dot on them.
So, fig.(1) is the only possible fig as it is having three blank faces adjacent to each other.

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Sol : Option B
Even numbered dice are: (II), (IV) and (VI)
Number of dots on the top face of (II) dice = 1
Number of dots on the top face of (IV) dice = 1
Number of dots on the top face of (VI) dice = 1
Therefore, the required total = 1+1+1=3